Zaymiey

⚛️ Physics  ·  Oscillations  ·  NEET & JEE

Two springs with constants k<sub>1</sub> and k<sub>2</sub> are connected in parallel supporting a mass m. The effective spring constant is:

Answer: k 1 + k 2.

  • A k<sub>1</sub> + k<sub>2</sub>
  • B k<sub>1</sub> k<sub>2</sub>/(k<sub>1</sub>+k<sub>2</sub>)
  • C k<sub>1</sub> - k<sub>2</sub>
  • D (k<sub>1</sub> + k<sub>2</sub>)/2

Correct answer: A. k<sub>1</sub> + k<sub>2</sub>

Explanation: Springs in parallel: k<sub>eff</sub> = k<sub>1</sub> + k<sub>2</sub> (both springs stretch/compress by the same amount). In series: 1/k<sub>eff</sub> = 1/k<sub>1</sub> + 1/k<sub>2</sub>.

Displacement, Velocity, Acceleration in SHMx(t)v(t)a(t)v leads x by 90°; a is exactly out of phase with x (a = −ω²x)

In SHM, displacement and velocity are 90° out of phase (v is maximum when x=0, and zero when x is extreme), while acceleration is always exactly opposite in sign to displacement, consistent with a = −ω²x.

Concept context

Simple harmonic motion, spring-mass, pendulum, energy in SHM, and resonance.

Read the full Oscillations notes →