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⚛️ Physics  ·  Oscillations  ·  NEET & JEE

Two springs with constants k1 and k2 are connected in parallel supporting a mass m. The effective spring constant is:

Answer: k1 + k2.

  • A k1 + k2
  • B k1 k2/(k1+k2)
  • C k1 - k2
  • D (k1 + k2)/2

Correct answer: A. k1 + k2

Explanation: Springs in parallel: keff = k1 + k2 (both springs stretch/compress by the same amount). In series: 1/keff = 1/k1 + 1/k2.

Displacement, Velocity, Acceleration in SHMx(t)v(t)a(t)v leads x by 90°; a is exactly out of phase with x (a = −ω²x)

In SHM, displacement and velocity are 90° out of phase (v is maximum when x=0, and zero when x is extreme), while acceleration is always exactly opposite in sign to displacement, consistent with a = −ω²x.

Concept context

Simple harmonic motion, spring-mass, pendulum, energy in SHM, and resonance.

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