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⚛️ Physics  ·  Oscillations  ·  NEET & JEE

The time period of a simple pendulum of length L is:

Answer: 2π√(L/g).

  • A 2π√(L/g)
  • B 2π√(g/L)
  • C π√(L/g)
  • D 2πL/g

Correct answer: A. 2π√(L/g)

Explanation: T = 2π√(L/g). This assumes small angle oscillations (θ < 15°) and is independent of the mass of the bob.

Displacement, Velocity, Acceleration in SHMx(t)v(t)a(t)v leads x by 90°; a is exactly out of phase with x (a = −ω²x)

In SHM, displacement and velocity are 90° out of phase (v is maximum when x=0, and zero when x is extreme), while acceleration is always exactly opposite in sign to displacement, consistent with a = −ω²x.

Concept context

Simple harmonic motion, spring-mass, pendulum, energy in SHM, and resonance.

Read the full Oscillations notes →