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⚛️ Physics  ·  Oscillations  ·  NEET & JEE

The projection of a particle in uniform circular motion onto a diameter executes:

Answer: Simple harmonic motion.

  • A Uniform circular motion
  • B Simple harmonic motion
  • C Non-uniform acceleration only
  • D Projectile motion

Correct answer: B. Simple harmonic motion

Explanation: The foot of the perpendicular from a uniformly rotating particle onto any diameter moves back and forth as x = A cos(ωt), which is exactly simple harmonic motion. This is the geometric basis of SHM.

Displacement, Velocity, Acceleration in SHMx(t)v(t)a(t)v leads x by 90°; a is exactly out of phase with x (a = −ω²x)

In SHM, displacement and velocity are 90° out of phase (v is maximum when x=0, and zero when x is extreme), while acceleration is always exactly opposite in sign to displacement, consistent with a = −ω²x.

Concept context

Simple harmonic motion, spring-mass, pendulum, energy in SHM, and resonance.

Read the full Oscillations notes →