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⚛️ Physics  ·  Oscillations  ·  NEET & JEE

Two SHMs x<sub>1</sub> = A sin(ωt) and x<sub>2</sub> = A sin(ωt + π/3) are superposed. The amplitude of the resultant is:

Answer: A√3.

  • A A√3
  • B A√2
  • C 2A
  • D A

Correct answer: A. A√3

Explanation: Resultant amplitude = √(A² + A² + 2A²cos(π/3)) = A√(2 + 2×1/2) = A√3.

Displacement, Velocity, Acceleration in SHMx(t)v(t)a(t)v leads x by 90°; a is exactly out of phase with x (a = −ω²x)

In SHM, displacement and velocity are 90° out of phase (v is maximum when x=0, and zero when x is extreme), while acceleration is always exactly opposite in sign to displacement, consistent with a = −ω²x.

Concept context

Simple harmonic motion, spring-mass, pendulum, energy in SHM, and resonance.

Read the full Oscillations notes →