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⚛️ Physics  ·  Oscillations  ·  NEET & JEE

Two identical springs each of constant k are connected in parallel and support a mass m. The period of oscillation is:

Answer: 2π√(m/2k).

  • A 2π√(m/2k)
  • B 2π√(2m/k)
  • C 2π√(m/k)
  • D 2π√(m/4k)

Correct answer: A. 2π√(m/2k)

Explanation: Parallel springs give effective constant 2k, so T = 2π√(m/2k).

Displacement, Velocity, Acceleration in SHMx(t)v(t)a(t)v leads x by 90°; a is exactly out of phase with x (a = −ω²x)

In SHM, displacement and velocity are 90° out of phase (v is maximum when x=0, and zero when x is extreme), while acceleration is always exactly opposite in sign to displacement, consistent with a = −ω²x.

Concept context

Simple harmonic motion, spring-mass, pendulum, energy in SHM, and resonance.

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