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⚛️ Physics  ·  Oscillations  ·  NEET & JEE

The time-averaged potential energy of an SHM particle equals:

Answer: Half the total energy.

  • A Half the total energy
  • B Total energy
  • C Zero
  • D The total kinetic energy

Correct answer: A. Half the total energy

Explanation: Average PE = (1/2) × (1/2)kA² = Total E/2. Similarly, average KE = Total E/2. They are equal and each half the total energy.

Displacement, Velocity, Acceleration in SHMx(t)v(t)a(t)v leads x by 90°; a is exactly out of phase with x (a = −ω²x)

In SHM, displacement and velocity are 90° out of phase (v is maximum when x=0, and zero when x is extreme), while acceleration is always exactly opposite in sign to displacement, consistent with a = −ω²x.

Concept context

Simple harmonic motion, spring-mass, pendulum, energy in SHM, and resonance.

Read the full Oscillations notes →