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⚛️ Physics  ·  Oscillations  ·  NEET & JEE

The potential energy of a spring-mass system executing SHM is (1/2)kx². If x = A sin(ωt), then PE averaged over a full cycle is:

Answer: kA²/4.

  • A kA²/4
  • B kA²/2
  • C kA²
  • D kA²/8

Correct answer: A. kA²/4

Explanation: PE = (1/2)kA² sin²(ωt). Average of sin² over a full cycle = 1/2. So avg PE = (1/2)kA² × (1/2) = kA²/4. Same as average KE.

Displacement, Velocity, Acceleration in SHMx(t)v(t)a(t)v leads x by 90°; a is exactly out of phase with x (a = −ω²x)

In SHM, displacement and velocity are 90° out of phase (v is maximum when x=0, and zero when x is extreme), while acceleration is always exactly opposite in sign to displacement, consistent with a = −ω²x.

Concept context

Simple harmonic motion, spring-mass, pendulum, energy in SHM, and resonance.

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