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⚛️ Physics  ·  Oscillations  ·  NEET & JEE

For a spring-mass system, the time period in a lift accelerating upward with acceleration a is:

Answer: 2π√(m/(k)) (same as before).

  • A 2π√(m/(k)) (same as before)
  • B 2π√(m(g+a)/k) in many documented cases
  • C 2π√(m(g-a)/k) according to conventional understanding
  • D Depends on mass in routine practice

Correct answer: A. 2π√(m/(k)) (same as before)

Explanation: For a spring-mass system, T = 2π√(m/k). This does NOT depend on gravity, so acceleration of lift has no effect. (For a pendulum, effective g changes, but not for spring-mass).

Displacement, Velocity, Acceleration in SHMx(t)v(t)a(t)v leads x by 90°; a is exactly out of phase with x (a = −ω²x)

In SHM, displacement and velocity are 90° out of phase (v is maximum when x=0, and zero when x is extreme), while acceleration is always exactly opposite in sign to displacement, consistent with a = −ω²x.

Concept context

Simple harmonic motion, spring-mass, pendulum, energy in SHM, and resonance.

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