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⚛️ Physics  ·  Oscillations  ·  NEET & JEE

At what position in SHM is the KE equal to twice the PE?

Answer: x = A/√3.

  • A x = A/√3
  • B x = A/2
  • C x = A/√2
  • D x = A/3

Correct answer: A. x = A/√3

Explanation: KE = 2 PE: (1/2)k(A²-x²) = 2(1/2)kx² → A² - x² = 2x² → A² = 3x² → x = A/√3.

Displacement, Velocity, Acceleration in SHMx(t)v(t)a(t)v leads x by 90°; a is exactly out of phase with x (a = −ω²x)

In SHM, displacement and velocity are 90° out of phase (v is maximum when x=0, and zero when x is extreme), while acceleration is always exactly opposite in sign to displacement, consistent with a = −ω²x.

Concept context

Simple harmonic motion, spring-mass, pendulum, energy in SHM, and resonance.

Read the full Oscillations notes →