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⚛️ Physics  ·  Oscillations  ·  NEET & JEE

A spring stretches by 0.2 m when a mass of 2 kg is hung from it. The time period of vertical oscillation is:

Answer: 0.897 s.

  • A 0.897 s
  • B 0.45 s
  • C 2.83 s
  • D 0.2 s

Correct answer: A. 0.897 s

Explanation: At equilibrium: kx = mg → k = mg/x = 2×10/0.2 = 100 N/m. T = 2π√(m/k) = 2π√(2/100) = 2π × 0.1414 ≈ 0.889 s.

Displacement, Velocity, Acceleration in SHMx(t)v(t)a(t)v leads x by 90°; a is exactly out of phase with x (a = −ω²x)

In SHM, displacement and velocity are 90° out of phase (v is maximum when x=0, and zero when x is extreme), while acceleration is always exactly opposite in sign to displacement, consistent with a = −ω²x.

Concept context

Simple harmonic motion, spring-mass, pendulum, energy in SHM, and resonance.

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