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⚛️ Physics  ·  Oscillations  ·  NEET & JEE

A spring of spring constant 200 N/m has a mass of 0.5 kg. What is the time period of oscillation?

Answer: 0.314 s.

  • A 0.314 s
  • B 3.14 s
  • C 0.0314 s
  • D 1 s

Correct answer: A. 0.314 s

Explanation: T = 2π√(m/k) = 2π√(0.5/200) = 2π√(0.0025) = 2π × 0.05 = 0.314 s.

Displacement, Velocity, Acceleration in SHMx(t)v(t)a(t)v leads x by 90°; a is exactly out of phase with x (a = −ω²x)

In SHM, displacement and velocity are 90° out of phase (v is maximum when x=0, and zero when x is extreme), while acceleration is always exactly opposite in sign to displacement, consistent with a = −ω²x.

Concept context

Simple harmonic motion, spring-mass, pendulum, energy in SHM, and resonance.

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