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⚛️ Physics  ·  Oscillations  ·  NEET & JEE

A particle performs SHM with amplitude 0.1 m and frequency 5 Hz. What is its maximum velocity?

Answer: π m/s.

  • A π m/s
  • B 0.5π m/s
  • C 2π m/s
  • D 5 m/s

Correct answer: A. π m/s

Explanation: v<sub>max</sub> = Aω = A × 2πf = 0.1 × 2π × 5 = π m/s ≈ 3.14 m/s.

Displacement, Velocity, Acceleration in SHMx(t)v(t)a(t)v leads x by 90°; a is exactly out of phase with x (a = −ω²x)

In SHM, displacement and velocity are 90° out of phase (v is maximum when x=0, and zero when x is extreme), while acceleration is always exactly opposite in sign to displacement, consistent with a = −ω²x.

Concept context

Simple harmonic motion, spring-mass, pendulum, energy in SHM, and resonance.

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