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⚛️ Physics  ·  Oscillations  ·  NEET & JEE

A particle in SHM has period 1.2 s. The time taken to move from the mean position to half the amplitude is:

Answer: 0.1 s.

  • A 0.2 s
  • B 0.1 s
  • C 0.3 s
  • D 0.6 s

Correct answer: B. 0.1 s

Explanation: With x = A sin(ωt), x = A/2 gives ωt = π/6, so t = T/12 = 1.2/12 = 0.1 s.

Displacement, Velocity, Acceleration in SHMx(t)v(t)a(t)v leads x by 90°; a is exactly out of phase with x (a = −ω²x)

In SHM, displacement and velocity are 90° out of phase (v is maximum when x=0, and zero when x is extreme), while acceleration is always exactly opposite in sign to displacement, consistent with a = −ω²x.

Concept context

Simple harmonic motion, spring-mass, pendulum, energy in SHM, and resonance.

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