Zaymiey

⚛️ Physics  ·  Oscillations  ·  NEET & JEE

A particle in SHM has displacement x = 4 sin(2πt) cm. Its maximum speed is:

Answer: 8 cm/s.

  • A 16π cm/s
  • B 4π cm/s
  • C 8π cm/s
  • D 2π cm/s

Correct answer: C. 8π cm/s

Explanation: Here amplitude A = 4 cm and &omega; = 2&pi; rad/s. Maximum speed v<sub>max</sub> = A&omega; = 4 &times; 2&pi; = 8&pi; cm/s (about 25.1 cm/s).

Displacement, Velocity, Acceleration in SHMx(t)v(t)a(t)v leads x by 90°; a is exactly out of phase with x (a = −ω²x)

In SHM, displacement and velocity are 90° out of phase (v is maximum when x=0, and zero when x is extreme), while acceleration is always exactly opposite in sign to displacement, consistent with a = −ω²x.

Concept context

Simple harmonic motion, spring-mass, pendulum, energy in SHM, and resonance.

Read the full Oscillations notes →