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⚛️ Physics  ·  Oscillations  ·  NEET & JEE

A particle in SHM has amplitude 5 cm and period 2 s. Its maximum speed is:

Answer: 0.157 m/s.

  • A 0.05 m/s
  • B 0.157 m/s
  • C 0.314 m/s
  • D 1 m/s

Correct answer: B. 0.157 m/s

Explanation: v<sub>max</sub> = Aω = 0.05·(2π/2) = 0.05π ≈ 0.157 m/s.

Displacement, Velocity, Acceleration in SHMx(t)v(t)a(t)v leads x by 90°; a is exactly out of phase with x (a = −ω²x)

In SHM, displacement and velocity are 90° out of phase (v is maximum when x=0, and zero when x is extreme), while acceleration is always exactly opposite in sign to displacement, consistent with a = −ω²x.

Concept context

Simple harmonic motion, spring-mass, pendulum, energy in SHM, and resonance.

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