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⚛️ Physics  ·  Oscillations  ·  NEET & JEE

A horizontal disk oscillates as a torsional pendulum. If the wire has torsional constant k<sub>T</sub> and the disk has MI I, the period is:

Answer: 2π√(I/k T ).

  • A 2π√(I/k<sub>T</sub>)
  • B 2π√(k<sub>T</sub>/I)
  • C 2π√(I/M)
  • D 2π√(I k<sub>T</sub>)

Correct answer: A. 2π√(I/k<sub>T</sub>)

Explanation: For torsional SHM: τ = -k<sub>T</sub> θ, giving Iα = -k<sub>T</sub> θ. ω² = k<sub>T</sub>/I. T = 2π√(I/k<sub>T</sub>).

Displacement, Velocity, Acceleration in SHMx(t)v(t)a(t)v leads x by 90°; a is exactly out of phase with x (a = −ω²x)

In SHM, displacement and velocity are 90° out of phase (v is maximum when x=0, and zero when x is extreme), while acceleration is always exactly opposite in sign to displacement, consistent with a = −ω²x.

Concept context

Simple harmonic motion, spring-mass, pendulum, energy in SHM, and resonance.

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