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⚛️ Physics  ·  Gravitation  ·  NEET & JEE

Total mechanical energy of a satellite in circular orbit of radius r (mass m, Earth mass M):

Answer: -GMm/(2r).

  • A -GMm/r
  • B -GMm/(2r)
  • C GMm/(2r)
  • D GMm/r

Correct answer: B. -GMm/(2r)

Explanation: KE = GMm/(2r), PE = -GMm/r. Total E = KE+PE = GMm/(2r) - GMm/r = -GMm/(2r). (Negative means bound system.)

Variation of g with Height and Depthgg_surfaceAbove surface: g ∝ 1/r² (falls off curving down)Below surface: g ∝ r (falls off LINEARLY)Earth's surface (r = R)centre (r=0): g=0g is MAXIMUM exactly at the surface - it decreases in both directions, but by different laws

g is maximum at Earth's surface; going up, it falls off as 1/r² (inverse-square); going down, it falls off linearly with depth (since only the mass enclosed within radius r contributes), reaching zero at the centre.

Concept context

Universal gravitation, orbital mechanics, gravitational potential, and escape velocity.

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