Zaymiey

⚛️ Physics  ·  Gravitation  ·  NEET & JEE

Value of gravitational acceleration g at Earth's surface is approximately:

Answer: 9.8 m/s 2.

  • A 9.8 m/s<sup>2</sup>
  • B 8.9 m/s<sup>2</sup>
  • C 10.8 m/s<sup>2</sup>
  • D 6.7 m/s<sup>2</sup>

Correct answer: A. 9.8 m/s<sup>2</sup>

Explanation: g = 9.8 m/s<sup>2</sup> approximately. For calculations, g = 10 m/s<sup>2</sup> is often used.

Variation of g with Height and Depthgg_surfaceAbove surface: g ∝ 1/r² (falls off curving down)Below surface: g ∝ r (falls off LINEARLY)Earth's surface (r = R)centre (r=0): g=0g is MAXIMUM exactly at the surface - it decreases in both directions, but by different laws

g is maximum at Earth's surface; going up, it falls off as 1/r² (inverse-square); going down, it falls off linearly with depth (since only the mass enclosed within radius r contributes), reaching zero at the centre.

Concept context

Universal gravitation, orbital mechanics, gravitational potential, and escape velocity.

Read the full Gravitation notes →