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⚛️ Physics  ·  Gravitation  ·  NEET & JEE

Escape velocity from Earth's surface is approximately:

Answer: 11.2 km/s.

  • A 7.9 km/s
  • B 11.2 km/s
  • C 3 km/s
  • D 28 km/s

Correct answer: B. 11.2 km/s

Explanation: Escape velocity = sqrt(2gR) = sqrt(2 x 9.8 x 6.4 x 10<sup>6</sup>) = approx 11.2 km/s.

Variation of g with Height and Depthgg_surfaceAbove surface: g ∝ 1/r² (falls off curving down)Below surface: g ∝ r (falls off LINEARLY)Earth's surface (r = R)centre (r=0): g=0g is MAXIMUM exactly at the surface - it decreases in both directions, but by different laws

g is maximum at Earth's surface; going up, it falls off as 1/r² (inverse-square); going down, it falls off linearly with depth (since only the mass enclosed within radius r contributes), reaching zero at the centre.

Concept context

Universal gravitation, orbital mechanics, gravitational potential, and escape velocity.

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