Zaymiey

⚛️ Physics  ·  Electrostatic Potential and Capacitance  ·  NEET & JEE

A capacitor C<sub>1</sub> = 4 microF and C<sub>2</sub> = 6 microF in series. Equivalent capacitance:

Answer: 2.4 microF.

  • A 2.4 microF
  • B 10 microF
  • C 1.5 microF
  • D 0.1 microF

Correct answer: A. 2.4 microF

Explanation: 1/C = 1/4 + 1/6 = 3/12 + 2/12 = 5/12. C = 12/5 = 2.4 microF.

Radial electric field lines and concentric red equipotential lines around a point charge (an electron), with field lines pointing inward

Field lines (radial) and equipotential lines (concentric circles) of a point charge. Equipotential surfaces are always perpendicular to the field lines. Image: Sjlegg, Public Domain, via Wikimedia Commons.

Concept context

Electric potential, equipotential surfaces, potential energy of charge systems, conductors, dielectrics, capacitors, combinations, and energy storage.

Read the full Electrostatic Potential and Capacitance notes →