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⚛️ Physics  ·  Electric Charges and Fields  ·  NEET & JEE

Two point charges +2 µC and -8 µC are 3 m apart. The point between them where the net electric field is zero is 1 m from the +2 µC charge. The electric potential at this point is:

Answer: -1.8 10 4 V.

  • A +1.8 &times; 10<sup>4</sup> V
  • B -9.0 &times; 10<sup>3</sup> V
  • C -1.8 &times; 10<sup>4</sup> V
  • D -3.6 &times; 10<sup>4</sup> V

Correct answer: C. -1.8 &times; 10<sup>4</sup> V

Explanation: At the zero-field point, the distances are 1 m and 2 m. V = k(2 &times; 10<sup>-6</sup>/1 - 8 &times; 10<sup>-6</sup>/2) = -1.8 &times; 10<sup>4</sup> V.

Field Lines: Single Charge vs Electric Dipole+isolated +charge: lines radiate outward, all directions+dipole: lines curve from + to − (denser between them)

Field lines always point from positive to negative charge, are denser where the field is stronger, and never cross; an isolated positive charge has lines radiating symmetrically outward, while a dipole's lines curve from the positive to the negative charge.

Concept context

Coulomb's law, electric field, potential, capacitors, Gauss's law.

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