Answer: zero.
- A dependent on the charge only
- B positive
- C negative
- D zero
Correct answer: D. zero
Explanation: The potential difference between any two points on an equipotential surface is zero, so W = qΔV = 0.
Field lines always point from positive to negative charge, are denser where the field is stronger, and never cross; an isolated positive charge has lines radiating symmetrically outward, while a dipole's lines curve from the positive to the negative charge.
Concept context
Coulomb's law, electric field, potential, capacitors, Gauss's law.