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⚛️ Physics  ·  Electric Charges and Fields  ·  NEET & JEE

Two charges +2 µC and -6 µC are separated by 0.4 m. The electric potential at the midpoint is:

Answer: -1.8 10 5 V.

  • A -2.7 &times; 10<sup>5</sup> V
  • B -9.0 &times; 10<sup>4</sup> V
  • C -1.8 &times; 10<sup>5</sup> V
  • D +1.8 &times; 10<sup>5</sup> V

Correct answer: C. -1.8 &times; 10<sup>5</sup> V

Explanation: Each charge is 0.2 m from the midpoint. V = k(q<sub>1</sub> + q<sub>2</sub>)/r = 9 &times; 10<sup>9</sup> &times; (-4 &times; 10<sup>-6</sup>)/0.2 = -1.8 &times; 10<sup>5</sup> V.

Field Lines: Single Charge vs Electric Dipole+isolated +charge: lines radiate outward, all directions+dipole: lines curve from + to − (denser between them)

Field lines always point from positive to negative charge, are denser where the field is stronger, and never cross; an isolated positive charge has lines radiating symmetrically outward, while a dipole's lines curve from the positive to the negative charge.

Concept context

Coulomb's law, electric field, potential, capacitors, Gauss's law.

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