Answer: 1/r.
- A 1/r<sup>2</sup>
- B 1/r
- C 1/sqrt(r)
- D 1/r<sup>3</sup>
Correct answer: B. 1/r
Explanation: V = kQ/r. Electric potential decreases as 1/r (not 1/r<sup>2</sup> like the field does).
Field lines always point from positive to negative charge, are denser where the field is stronger, and never cross; an isolated positive charge has lines radiating symmetrically outward, while a dipole's lines curve from the positive to the negative charge.
Concept context
Coulomb's law, electric field, potential, capacitors, Gauss's law.