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⚛️ Physics  ·  Electric Charges and Fields  ·  NEET & JEE

A short electric dipole has dipole moment 4 &times; 10<sup>-8</sup> C m. At a point 0.2 m away on its axial line, the far-field electric potential is approximately:

Answer: 9.0 10 3 V.

  • A 9.0 &times; 10<sup>3</sup> V
  • B 1.8 &times; 10<sup>4</sup> V
  • C 4.5 &times; 10<sup>3</sup> V
  • D 3.6 &times; 10<sup>4</sup> V

Correct answer: A. 9.0 &times; 10<sup>3</sup> V

Explanation: For a short dipole, V = kp cos&theta;/r<sup>2</sup>. On the axis cos&theta; = 1, so V = 9 &times; 10<sup>9</sup> &times; 4 &times; 10<sup>-8</sup>/0.2<sup>2</sup> = 9.0 &times; 10<sup>3</sup> V.

Field Lines: Single Charge vs Electric Dipole+isolated +charge: lines radiate outward, all directions+dipole: lines curve from + to − (denser between them)

Field lines always point from positive to negative charge, are denser where the field is stronger, and never cross; an isolated positive charge has lines radiating symmetrically outward, while a dipole's lines curve from the positive to the negative charge.

Concept context

Coulomb's law, electric field, potential, capacitors, Gauss's law.

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