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⚛️ Physics  ·  Dual Nature of Radiation and Matter  ·  NEET & JEE

Two metals A and B are illuminated by the same monochromatic light. Their stopping potentials are 1.2 V and 0.7 V respectively. What is the difference between their work functions?

Answer: 0.5 eV.

  • A 0.2 eV
  • B 0.3 eV
  • C 0.5 eV
  • D 1.9 eV

Correct answer: C. 0.5 eV

Explanation: For the same incident frequency, the photon energy is the same. From K<sub>max</sub> = h&nu; - &phi; = eV<sub>0</sub>, the difference in work functions equals e times the difference in stopping potentials. Thus the difference is 1.2 - 0.7 = 0.5 eV.

evacuated tubelightmetal platee⁻e⁻e⁻collectorAbattery (variable)

In the photoelectric setup, light striking the metal plate ejects electrons that cross the evacuated tube to the collector, producing a measurable current on the ammeter.

Concept context

Photoelectric effect, de Broglie waves, Bohr's model, atomic spectra.

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