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⚛️ Physics  ·  Dual Nature of Radiation and Matter  ·  NEET & JEE

Light of wavelength 400 nm falls on a metal with work function 2.0 eV. Taking hc = 1240 eV nm, what is the stopping potential?

Answer: 1.50 V.

  • A 1.50 V
  • B 0.80 V
  • C 1.10 V
  • D 0.50 V

Correct answer: A. 1.50 V

Explanation: Photon energy = 1240/400 = 3.10 eV. Therefore K<sub>max</sub> = 3.10 - 2.0 = 1.10 eV. Since eV<sub>0</sub> = K<sub>max</sub>, the stopping potential is 1.10 V.

evacuated tubelightmetal platee⁻e⁻e⁻collectorAbattery (variable)

In the photoelectric setup, light striking the metal plate ejects electrons that cross the evacuated tube to the collector, producing a measurable current on the ammeter.

Concept context

Photoelectric effect, de Broglie waves, Bohr's model, atomic spectra.

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