Answer: Number of emitted electrons (photocurrent).
- A The maximum kinetic energy of each emitted electron
- B The threshold frequency needed to eject electrons
- C Number of emitted electrons (photocurrent)
- D The stopping potential needed to halt the electrons
Correct answer: C. Number of emitted electrons (photocurrent)
Explanation: Higher intensity = more photons per second = more electrons emitted per second = higher photocurrent. KE is unaffected.
In the photoelectric setup, light striking the metal plate ejects electrons that cross the evacuated tube to the collector, producing a measurable current on the ammeter.
Concept context
Photoelectric effect, de Broglie waves, Bohr's model, atomic spectra.