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⚛️ Physics  ·  Dual Nature of Radiation and Matter  ·  NEET & JEE

De Broglie wavelength of a particle with momentum p is lambda =

Answer: h/p.

  • A h/p
  • B hp
  • C h/p²
  • D p/h

Correct answer: A. h/p

Explanation: De Broglie: lambda = h/p where h = Planck constant and p = momentum. Applies to all matter.

evacuated tubelightmetal platee⁻e⁻e⁻collectorAbattery (variable)

In the photoelectric setup, light striking the metal plate ejects electrons that cross the evacuated tube to the collector, producing a measurable current on the ammeter.

Concept context

Photoelectric effect, de Broglie waves, Bohr's model, atomic spectra.

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