Zaymiey

⚛️ Physics  ·  Dual Nature of Radiation and Matter  ·  NEET & JEE

An electron and a proton are moving with equal kinetic energies. What is the ratio of their de Broglie wavelengths, &lambda;<sub>e</sub>/&lambda;<sub>p</sub>?

Answer: 1836.

  • A 1/&radic;1836
  • B 1836
  • C &radic;1836
  • D 1/1836

Correct answer: C. &radic;1836

Explanation: For non-relativistic particles, &lambda; = h/&radic;(2mK). At equal kinetic energy, &lambda; is proportional to 1/&radic;m. Thus &lambda;<sub>e</sub>/&lambda;<sub>p</sub> = &radic;(m<sub>p</sub>/m<sub>e</sub>) = &radic;1836.

evacuated tubelightmetal platee⁻e⁻e⁻collectorAbattery (variable)

In the photoelectric setup, light striking the metal plate ejects electrons that cross the evacuated tube to the collector, producing a measurable current on the ammeter.

Concept context

Photoelectric effect, de Broglie waves, Bohr's model, atomic spectra.

Read the full Dual Nature of Radiation and Matter notes →