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🧪 Chemistry  ·  Haloalkanes & Haloarenes  ·  NEET & JEE

When 1,2-dibromoethane is treated with Zn metal, the product is:

Answer: Ethene (elimination of both Br via zinc).

  • A Ethane, formed by simple reductive removal of both bromine atoms with hydrogen
  • B Ethene (elimination of both Br via zinc)
  • C 1,2-ethanediol, formed by hydrolytic substitution of both bromine atoms
  • D Zinc bromide only, with no organic product formed in the reaction

Correct answer: B. Ethene (elimination of both Br via zinc)

Explanation: Zinc brings about dehalogenation (removal of two adjacent halogens); the electrons push out both Br atoms and form ethene (a double bond). This is the reverse of bromination of ethene.

SN2: one stepNu-CX-backside attackNuC+ X-Inversion of configuration(Walden inversion)SN1: two stepsCX-slow: leaving group exits+CcarbocationNu-Planar intermediate givesracemisation (both faces attacked)

SN2 proceeds in a single step with backside attack and inversion of configuration, while SN1 forms a planar carbocation intermediate first, leading to racemisation.

Concept context

Study carbon-halogen compounds: how they are made, how they react via SN1/SN2 and elimination, their stereochemistry, and their environmental impact.

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