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🧪 Chemistry  ·  Haloalkanes & Haloarenes  ·  NEET & JEE

The C-X bond length order in haloalkanes is:

Answer: C-F < C-Cl < C-Br < C-I.

  • A C-F < C-Cl < C-Br < C-I
  • B C-I < C-Br < C-Cl < C-F
  • C C-F = C-Cl = C-Br = C-I
  • D C-Cl < C-F < C-Br < C-I

Correct answer: A. C-F < C-Cl < C-Br < C-I

Explanation: Bond length increases as the halogen gets larger: C-F is shortest and C-I is longest.

SN2: one stepNu-CX-backside attackNuC+ X-Inversion of configuration(Walden inversion)SN1: two stepsCX-slow: leaving group exits+CcarbocationNu-Planar intermediate givesracemisation (both faces attacked)

SN2 proceeds in a single step with backside attack and inversion of configuration, while SN1 forms a planar carbocation intermediate first, leading to racemisation.

Concept context

Study carbon-halogen compounds: how they are made, how they react via SN1/SN2 and elimination, their stereochemistry, and their environmental impact.

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