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🧪 Chemistry  ·  Haloalkanes & Haloarenes  ·  NEET & JEE

What is the product of the reaction between benzyl bromide (C<sub>6</sub>H<sub>5</sub>CH<sub>2</sub>Br) and aqueous NaOH?

Answer: Benzyl alcohol (C 6 H 5 CH 2 OH).

  • A Chlorobenzene in the majority of cases studied
  • B Benzaldehyde as widely reported
  • C Benzyl alcohol (C<sub>6</sub>H<sub>5</sub>CH<sub>2</sub>OH)
  • D Phenol in standard practice

Correct answer: C. Benzyl alcohol (C<sub>6</sub>H<sub>5</sub>CH<sub>2</sub>OH)

Explanation: Benzyl bromide has Br on a sp³ carbon (benzylic position, not on the ring); it undergoes SN2/SN1 substitution with OH⁻ to give benzyl alcohol.

SN2: one stepNu-CX-backside attackNuC+ X-Inversion of configuration(Walden inversion)SN1: two stepsCX-slow: leaving group exits+CcarbocationNu-Planar intermediate givesracemisation (both faces attacked)

SN2 proceeds in a single step with backside attack and inversion of configuration, while SN1 forms a planar carbocation intermediate first, leading to racemisation.

Concept context

Study carbon-halogen compounds: how they are made, how they react via SN1/SN2 and elimination, their stereochemistry, and their environmental impact.

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