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🧪 Chemistry  ·  Haloalkanes & Haloarenes  ·  NEET & JEE

The SN1 reaction of (R)-2-bromobutane with dilute NaOH gives:

Answer: A racemic mixture of (R)- and (S)-2-butanol.

  • A Mainly the (R)-2-butanol product with complete retention of configuration
  • B Mainly the (S)-2-butanol product via complete inversion of configuration
  • C A racemic mixture of (R)- and (S)-2-butanol
  • D No observable reaction since dilute NaOH cannot attack a secondary halide

Correct answer: C. A racemic mixture of (R)- and (S)-2-butanol

Explanation: SN1 forms a planar carbocation intermediate; the nucleophile can attack from either face, giving a racemic (50:50) mixture of enantiomers.

SN2: one stepNu-CX-backside attackNuC+ X-Inversion of configuration(Walden inversion)SN1: two stepsCX-slow: leaving group exits+CcarbocationNu-Planar intermediate givesracemisation (both faces attacked)

SN2 proceeds in a single step with backside attack and inversion of configuration, while SN1 forms a planar carbocation intermediate first, leading to racemisation.

Concept context

Study carbon-halogen compounds: how they are made, how they react via SN1/SN2 and elimination, their stereochemistry, and their environmental impact.

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