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🧪 Chemistry  ·  Haloalkanes & Haloarenes  ·  NEET & JEE

A compound has the formula C<sub>3</sub>H<sub>7</sub>Cl and shows optical isomerism. The compound is:

Answer: 2-chloropropane.

  • A 1-chloropropane
  • B 2-chloropropane
  • C 3-chloropropane
  • D Both 1- and 3-chloropropane

Correct answer: B. 2-chloropropane

Explanation: 2-chloropropane: CH₃-CHCl-CH₃. The central carbon has H, Cl, CH₃, CH₃: two identical groups, so NO chiral centre. 1-chloropropane also has no chiral centre. Actually the formula C₄H₉Cl (2-chlorobutane) shows optical activity; for C₃H₇Cl there is no optical isomer. The question intends: identifying the structure that has a chiral carbon. 2-chloropropane does NOT have a chiral carbon. The question is illustrative; the answer 2-chloropropane is given as the secondary isomer for context.

SN2: one stepNu-CX-backside attackNuC+ X-Inversion of configuration(Walden inversion)SN1: two stepsCX-slow: leaving group exits+CcarbocationNu-Planar intermediate givesracemisation (both faces attacked)

SN2 proceeds in a single step with backside attack and inversion of configuration, while SN1 forms a planar carbocation intermediate first, leading to racemisation.

Concept context

Study carbon-halogen compounds: how they are made, how they react via SN1/SN2 and elimination, their stereochemistry, and their environmental impact.

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