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🧪 Chemistry  ·  Coordination Compounds  ·  NEET & JEE

Which of the following is an outer orbital complex (uses nd orbitals, sp<sup>3</sup>d<sup>2</sup>)?

Answer: [CoF6]3- (F- is weak field, uses 4d orbitals, sp 3 d 2 , high spin).

  • A [CoF6]3- (F- is weak field, uses 4d orbitals, sp<sup>3</sup>d<sup>2</sup>, high spin)
  • B [Co(CN)6]3-, an inner orbital low-spin complex using 3d orbitals
  • C [Co(NH<sub>3</sub>)<sub>6</sub>]3-, an inner orbital low-spin complex using 3d orbitals
  • D [Fe(CO)<sub>5</sub>], a zero-valent carbonyl complex with trigonal bipyramidal geometry

Correct answer: A. [CoF6]3- (F- is weak field, uses 4d orbitals, sp<sup>3</sup>d<sup>2</sup>, high spin)

Explanation: [CoF6]3-: F- is weak field; outer orbital hybridisation uses 4s, 4p, 4d (not 3d); it is high spin with 4 unpaired electrons.

Octahedralcoordination no. 6e.g. [Co(NH3)6]3+Tetrahedralcoordination no. 4e.g. [Ni(CO)4]Square Planarcoordination no. 4e.g. [Pt(NH3)2Cl2]

The three common coordination geometries: octahedral (6 ligands), tetrahedral (4 ligands), and square planar (4 ligands in one plane).

Concept context

Study of compounds where a central metal atom is bonded to surrounding ligands. Covers nomenclature, types of isomerism, bonding theories (VBT, CFT), and applications in medicine, photography, and industry.

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