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🧪 Chemistry  ·  Coordination Compounds  ·  NEET & JEE

The number of unpaired electrons in the octahedral complex [CoF<sub>6</sub>]<sup>3-</sup> is:

Answer: 4.

  • A 0
  • B 2
  • C 1
  • D 4

Correct answer: D. 4

Explanation: Co<sup>3+</sup> is d<sup>6</sup>; F<sup>-</sup> is a weak field ligand, so it is high spin t<sub>2g</sub><sup>4</sup>e<sub>g</sub><sup>2</sup> with 4 unpaired electrons (unlike low-spin [Co(NH<sub>3</sub>)<sub>6</sub>]<sup>3+</sup>).

Octahedralcoordination no. 6e.g. [Co(NH3)6]3+Tetrahedralcoordination no. 4e.g. [Ni(CO)4]Square Planarcoordination no. 4e.g. [Pt(NH3)2Cl2]

The three common coordination geometries: octahedral (6 ligands), tetrahedral (4 ligands), and square planar (4 ligands in one plane).

Concept context

Study of compounds where a central metal atom is bonded to surrounding ligands. Covers nomenclature, types of isomerism, bonding theories (VBT, CFT), and applications in medicine, photography, and industry.

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