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🧪 Chemistry  ·  Coordination Compounds  ·  NEET & JEE

The hybridisation of the central metal in the square planar [Ni(CN)<sub>4</sub>]<sup>2-</sup> is:

Answer: dsp 2.

  • A sp<sup>3</sup>
  • B sp<sup>3</sup>d
  • C dsp<sup>2</sup>
  • D d<sup>2</sup>sp<sup>3</sup>

Correct answer: C. dsp<sup>2</sup>

Explanation: Ni<sup>2+</sup> (d<sup>8</sup>) with strong-field CN<sup>-</sup> pairs its electrons, freeing a 3d orbital; dsp<sup>2</sup> hybridisation gives a diamagnetic square planar complex.

Octahedralcoordination no. 6e.g. [Co(NH3)6]3+Tetrahedralcoordination no. 4e.g. [Ni(CO)4]Square Planarcoordination no. 4e.g. [Pt(NH3)2Cl2]

The three common coordination geometries: octahedral (6 ligands), tetrahedral (4 ligands), and square planar (4 ligands in one plane).

Concept context

Study of compounds where a central metal atom is bonded to surrounding ligands. Covers nomenclature, types of isomerism, bonding theories (VBT, CFT), and applications in medicine, photography, and industry.

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