Answer: -0.4 Delta_o (4 in t 2g × -0.4 + 2 in eg × +0.6 = -1.6 + 1.2 = -0.4 Delta_o).
- A -0.4 Delta_o (4 in t<sub>2g</sub> × -0.4 + 2 in eg × +0.6 = -1.6 + 1.2 = -0.4 Delta_o)
- B Zero, since the high-spin d<sup>6</sup> arrangement gives no net stabilisation
- C -1.2 Delta_o, the value corresponding instead to a d<sup>3</sup> configuration
- D -2.4 Delta_o, the value corresponding instead to a low-spin d<sup>6</sup> configuration
Correct answer: A. -0.4 Delta_o (4 in t<sub>2g</sub> × -0.4 + 2 in eg × +0.6 = -1.6 + 1.2 = -0.4 Delta_o)
Explanation: d<sup>6</sup> high spin: t2g4 eg2. CFSE = 4(-0.4) + 2(+0.6) = -1.6 + 1.2 = -0.4 Delta_o.
The three common coordination geometries: octahedral (6 ligands), tetrahedral (4 ligands), and square planar (4 ligands in one plane).
Concept context
Study of compounds where a central metal atom is bonded to surrounding ligands. Covers nomenclature, types of isomerism, bonding theories (VBT, CFT), and applications in medicine, photography, and industry.