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🧪 Chemistry  ·  Coordination Compounds  ·  NEET & JEE

For a low-spin d<sup>6</sup> octahedral complex, the crystal field stabilisation energy (excluding pairing energy) is:

Answer: -2.4 Delta o.

  • A -2.4 Delta<sub>o</sub>
  • B -1.6 Delta<sub>o</sub>
  • C -0.4 Delta<sub>o</sub>
  • D -1.2 Delta<sub>o</sub>

Correct answer: A. -2.4 Delta<sub>o</sub>

Explanation: Low-spin d<sup>6</sup> is t<sub>2g</sub><sup>6</sup>e<sub>g</sub><sup>0</sup>. CFSE = 6(-0.4) + 0(+0.6) = -2.4 Delta<sub>o</sub> (pairing energy is added separately).

Octahedralcoordination no. 6e.g. [Co(NH3)6]3+Tetrahedralcoordination no. 4e.g. [Ni(CO)4]Square Planarcoordination no. 4e.g. [Pt(NH3)2Cl2]

The three common coordination geometries: octahedral (6 ligands), tetrahedral (4 ligands), and square planar (4 ligands in one plane).

Concept context

Study of compounds where a central metal atom is bonded to surrounding ligands. Covers nomenclature, types of isomerism, bonding theories (VBT, CFT), and applications in medicine, photography, and industry.

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