Zaymiey

🧪 Chemistry  ·  Coordination Compounds  ·  NEET & JEE

Compared with [Fe(H<sub>2</sub>O)<sub>6</sub>]<sup>3+</sup>, the ion [Fe(CN)<sub>6</sub>]<sup>3-</sup> has:

Answer: fewer unpaired electrons and is low spin.

  • A more unpaired electrons and is high spin
  • B the same number of unpaired electrons
  • C fewer unpaired electrons and is low spin
  • D no d electrons at all

Correct answer: C. fewer unpaired electrons and is low spin

Explanation: Both are Fe<sup>3+</sup> (d<sup>5</sup>). H<sub>2</sub>O (weak field) gives high spin, 5 unpaired; CN<sup>-</sup> (strong field) gives low spin, 1 unpaired. So the cyanide complex has fewer unpaired electrons.

Octahedralcoordination no. 6e.g. [Co(NH3)6]3+Tetrahedralcoordination no. 4e.g. [Ni(CO)4]Square Planarcoordination no. 4e.g. [Pt(NH3)2Cl2]

The three common coordination geometries: octahedral (6 ligands), tetrahedral (4 ligands), and square planar (4 ligands in one plane).

Concept context

Study of compounds where a central metal atom is bonded to surrounding ligands. Covers nomenclature, types of isomerism, bonding theories (VBT, CFT), and applications in medicine, photography, and industry.

Read the full Coordination Compounds notes →