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🧪 Chemistry  ·  Coordination Compounds  ·  NEET & JEE

Compared with [Fe(H2O)6]3+, the ion [Fe(CN)6]3- has:

Answer: fewer unpaired electrons and is low spin.

  • A more unpaired electrons and is high spin
  • B the same number of unpaired electrons
  • C fewer unpaired electrons and is low spin
  • D no d electrons at all

Correct answer: C. fewer unpaired electrons and is low spin

Explanation: Both are Fe3+ (d5). H2O (weak field) gives high spin, 5 unpaired; CN- (strong field) gives low spin, 1 unpaired. So the cyanide complex has fewer unpaired electrons.

Octahedralcoordination no. 6e.g. [Co(NH3)6]3+Tetrahedralcoordination no. 4e.g. [Ni(CO)4]Square Planarcoordination no. 4e.g. [Pt(NH3)2Cl2]

The three common coordination geometries: octahedral (6 ligands), tetrahedral (4 ligands), and square planar (4 ligands in one plane).

Concept context

Study of compounds where a central metal atom is bonded to surrounding ligands. Covers nomenclature, types of isomerism, bonding theories (VBT, CFT), and applications in medicine, photography, and industry.

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