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🧪 Chemistry  ·  Chemical Bonding and Molecular Structure  ·  NEET & JEE

The hybridisation of the sulfur atom in the SF<sub>4</sub> molecule is:

Answer: sp 3 d.

  • A sp<sup>3</sup>
  • B sp<sup>3</sup>d
  • C sp<sup>2</sup>
  • D sp<sup>3</sup>d<sup>2</sup>

Correct answer: B. sp<sup>3</sup>d

Explanation: SF<sub>4</sub> has 4 bond pairs and 1 lone pair (5 electron domains), requiring sp<sup>3</sup>d hybridisation and giving a see-saw shape.

Linear180 deg, e.g. CO2Trigonal Planar120 deg, e.g. BF3Tetrahedral109.5 deg, e.g. CH4Trigonal Bipyramidale.g. PCl5Octahedrale.g. SF6

VSEPR theory predicts molecular shape from the number of bonding and lone electron pairs around the central atom.

Concept context

Understand how atoms join to form molecules. Covers ionic and covalent bonding, VSEPR theory, hybridization (sp, sp², sp³), molecular orbital theory, bond polarity, and intermolecular forces like hydrogen bonding.

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