Answer: 616 J/K.
- A 168 J/K
- B 336 J/K
- C 616 J/K
- D 168000 J/K
Correct answer: C. 616 J/K
Explanation: Q = mL = 0.5 x 336000 = 168000 J. T = 273 K. delta S = Q/T = 168000/273 = 615.4 J/K approximately 616 J/K.
The Carnot cycle alternates two isothermal steps (heat absorbed at TH, released at TC) with two adiabatic steps (no heat exchange); the enclosed loop area equals the net work output, and η = 1−TC/TH is the maximum possible efficiency between those two temperatures.
Concept context
Laws of thermodynamics, heat engines, entropy, and gas processes.