Answer: 6235 J.
- A 1247 J
- B 4157 J
- C 6235 J
- D 8314 J
Correct answer: C. 6235 J
Explanation: Q = n Cv delta T = 1 x (5/2 x 8.314) x 300 = 5/2 x 8.314 x 300 = 6235.5 J.
The Carnot cycle alternates two isothermal steps (heat absorbed at TH, released at TC) with two adiabatic steps (no heat exchange); the enclosed loop area equals the net work output, and η = 1−TC/TH is the maximum possible efficiency between those two temperatures.
Concept context
Laws of thermodynamics, heat engines, entropy, and gas processes.