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⚛️ Physics  ·  System of Particles and Rotational Motion  ·  NEET & JEE

Two masses of 3 kg and 5 kg are fixed at the ends of a light rod of length 0.8 m. The distance of the centre of mass from the 3 kg mass is:

Answer: 0.5 m.

  • A 0.3 m
  • B 0.4 m
  • C 0.5 m
  • D 0.6 m

Correct answer: C. 0.5 m

Explanation: x = (m<sub>2</sub>d)/(m<sub>1</sub> + m<sub>2</sub>) = (5 × 0.8)/(3 + 5) = 4/8 = 0.5 m from the 3 kg mass.

axis OPr⊥Fττ = r⊥ × F = r × F × sinθ

Torque about axis O equals the force F multiplied by the perpendicular distance r⊥ from the axis to the line of action of the force, producing rotation.

Concept context

Moment of inertia, torque, angular momentum, rolling motion. Very high JEE weightage.

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