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⚛️ Physics  ·  System of Particles and Rotational Motion  ·  NEET & JEE

Two equal masses m are at the ends of a rod of negligible mass, length 2a. The rod rotates about its centre at ω. One mass suddenly falls off. What happens to ω?

Answer: ω doubles.

  • A ω doubles
  • B ω halves
  • C ω stays the same
  • D ω increases to √2 ω

Correct answer: A. ω doubles

Explanation: When a mass falls off, external torque is impulsive for an instant. Immediately after, I = ma² (one mass). By conservation of angular momentum: 2ma² ω = ma² ω' → ω' = 2ω.

axis OPr⊥Fττ = r⊥ × F = r × F × sinθ

Torque about axis O equals the force F multiplied by the perpendicular distance r⊥ from the axis to the line of action of the force, producing rotation.

Concept context

Moment of inertia, torque, angular momentum, rolling motion. Very high JEE weightage.

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