Answer: 7MR²/5.
- A 2MR²/5
- B 7MR²/5
- C 7MR²/2
- D MR²
Correct answer: B. 7MR²/5
Explanation: By the parallel-axis theorem: I = (2/5)MR² + MR² = 7MR²/5.
Torque about axis O equals the force F multiplied by the perpendicular distance r⊥ from the axis to the line of action of the force, producing rotation.
Concept context
Moment of inertia, torque, angular momentum, rolling motion. Very high JEE weightage.
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