Answer: ω = √(g/L cosθ).
- A ω = √(g/L cosθ)
- B ω = √(g/L)
- C ω = √(g tanθ/r)
- D ω = √(g/r)
Correct answer: A. ω = √(g/L cosθ)
Explanation: T cosθ = mg and T sinθ = mω²r where r = L sinθ. Dividing: tanθ = ω²r/g = ω² L sinθ/g → ω = √(g/L cosθ).
Torque about axis O equals the force F multiplied by the perpendicular distance r⊥ from the axis to the line of action of the force, producing rotation.
Concept context
Moment of inertia, torque, angular momentum, rolling motion. Very high JEE weightage.
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