⚛️ Physics · System of Particles and Rotational Motion · NEET & JEE

A solid ball rolling without slipping on a curved bowl oscillates about the bottom. The effective restoring force gives period T = 2π√(7R/5g) for a bowl of radius R. This is analogous to a pendulum of effective length:

Answer: 7R/5.

A 7R/5
B R
C 5R/7
D R/5

Correct answer: A. 7R/5

Explanation: For a simple pendulum, T = 2π√(L<sub>eff</sub>/g). Comparing, L<sub>eff</sub> = 7R/5. The rolling condition adds the factor of 7/5 compared to a sliding particle.

Torque about axis O equals the force F multiplied by the perpendicular distance r⊥ from the axis to the line of action of the force, producing rotation.

Concept context

Moment of inertia, torque, angular momentum, rolling motion. Very high JEE weightage.

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A solid ball rolling without slipping on a curved bowl oscillates about the bottom. The effective restoring force gives period T = 2π√(7R/5g) for a bowl of radius R. This is analogous to a pendulum of effective length:

Concept context

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