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⚛️ Physics  ·  System of Particles and Rotational Motion  ·  NEET & JEE

A rod of length L stands vertically on a frictionless floor and falls. What is the angular velocity when it hits the floor?

Answer: √(3g/L).

  • A √(3g/L)
  • B √(g/L)
  • C √(2g/L)
  • D √(6g/L)

Correct answer: A. √(3g/L)

Explanation: Energy conservation: mg(L/2) = (1/2)(ML²/3)ω². Solving: ω = √(3g/L). The CM falls by L/2.

axis OPr⊥Fττ = r⊥ × F = r × F × sinθ

Torque about axis O equals the force F multiplied by the perpendicular distance r⊥ from the axis to the line of action of the force, producing rotation.

Concept context

Moment of inertia, torque, angular momentum, rolling motion. Very high JEE weightage.

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